CXC CSEC January 2010 exam timetable
CXC has just published the final timetable for the January 2010 CSEC exams.
The CXC CSEC exams for January 2010 begin on Monday 4th January, 2010
The CXC CSEC exams for January 2010 ends on Tuesday 19h January, 2010.
We have posted a copy of the CXC CSEC January 2010 timetable to our community. We encourage our members and guests to use it in planning their study timetable for exams.
The CXC CSEC general proficiency English A exam is set to take place on Monday 4th January 2010.
The CXC CSEC general proficiency math exam is set to take place on Tuesday 5th January 2010.
Re: register late?
I think late registrations are over for the January 2010 CXC exams. You might want to look at signing up for the May/June 2010 CXC exams. Registrations for those exams are going on now...
Re: Re: register late?
hi good day i register for my exam in january and i did not recive a slip
Re: CXC fees
The CXC exam fees are posted here. Put CXC fees into the search engine and you should see the posting.
Exams in January
I didn't even got the chance to register for the exams in January, and the school that I'm attending hasn't even distribute the forms for the exams coming in May and June.
Re: Location?
You are usually told your exam center on the examination slip you receive. It has the subjects, the date of the exams, the time of the exams, the center, your candidate number and all that.
i need help
my name is sherika an i am doin maths in 18 days fr now can someone plz help me wit ma maths work i kinda dont remember how to do them....
or can u at least ans these question plz an thnx in advance ...
1.using a calculator or otherwise determine the EXCAT value of
_______
(3.9 * 0.27) + \/ 0.6724
2.express as a single fraction
2 1/2 - 4/5
_________
3/4
3.find the value of EACH of the following when a=2, b=-1,c=3
(i) a(a+c)
2
(ii) 4b - 2ac
_______
a+b+c
I can help
but you need to write the maths prob better what does that straight line mean square?
2. 2 1/2 - 4/5 all divide by 3/4
=5/2 - 4/5
25 -8
__________ = 17/10 = 1 7/10
10
a=2 b= -1 c=3
a(a+b)
2(2+ -1)
4-2
2
NB negative * negative = positive
positive * negative = negative
negative * positive = negative
positive * positive = positive
(ii) 4b - 2ac all over a+b+c
= 4(-1) - 2(2*3)
-4 -12
-16
-16/2*-1*3
=-16/-6 2 4/6
yuh work
(3.9*0.27)+ square root 0.6724
= 1.053 + 0.82
= 1.873
2 1/2 - 4/5
____________
3/4
= 5/2 - 4/5
__25-_8_____ = 17/10
10
17/10 divided by 3/4 =yuh dont divide fractions so yuh flip it.
17/10 * 4/3 = 34/15
answer = 34/15
a=2, b=-1, c= 3
a(a+c)
=2(-1+3)
=2(2)
=4
4b-2ac
__________ =
a+b+c
4(-1)-2(2*3)
____________
2+(-1)+ 3
(-4)-12
________ = -16/4 = -4
4
hey
U need 2 solve the brackets first, then the square root and then u add.
3.9*0.27=1.053
the square root of 0.6724 is 0.82
1.053+0.82=1.873
2.2 1/2=5/2
5/2-4/5
Find the Lcm then -
5/2-4/5
------
10
=5*5=25 4*2=8
25-8
-----
10
=18/10this can be reduced. 2 into 18 9 and 2 into 10 is 5. the answer is 9/5
now divide by 3/4
9/5/3/4
9/5*4/3=12/5 or 2 2/5
3. 2(2+3)=4+6=10
4. 4*(-1)-2(2)(3)=-4-12=-16
-16/2+(-1)+3=4
-16/4
=4
integrated science
hi,
can anyone tell me if there is an integrated Science csec january exam or is integrated science only written in june??
integrated sci in Jan
what about looking at a CXC January timetable, you think that might help you get an answer?
Wow Janaury 2010 timetable already?
CXC has put out the timetable for January 2010 exams already?? The results for June 2009 exams aren't even out yet.
Well, I guess by the time everybody gets results for CXC exams June 2009, they can start organizing the hook up for January 2010, if they need to.